National Cipher Challenge 2019 › Forums › National Cipher Challenge 2019: Countdown to Catastrophe › 9A helps please
18th December 2019 at 10:29 am #44991_sherlock_Member
Harry please give us a hint about 9A19th December 2019 at 11:54 pm #44998EpicgeethMember
How did you solve 8A?20th December 2019 at 11:37 pm #44997
That’s one easy cipher for some, one hard cipher for others but you have done it before!23rd December 2019 at 10:10 am #45015CribbageMember
This should get the prize for hint of the year!
Although perhaps it should be ‘one hard cipher for some, and an easy one for others …’.23rd December 2019 at 6:43 pm #45035PinguMember
@the-letter-wriggler by done it before, do you mean the type of cipher has been used this year or has been used in the cipher challenge in the past?24th December 2019 at 4:14 pm #45044
Hi Pingu, please see Epicgeeth above, that was not a request but a statement, couple it with my cryptic clue and maybe you will be successful. All the best and have a nice holiday.25th December 2019 at 9:34 am #45051
Sorry Pingu, I have just realised there is a chance that you may have solved 8A as was intended by Harry.
I will have to refer you to the statement I made in the tread HOW TO DO 8A for my information to be correct.27th December 2019 at 10:21 am #45033
Ho my, such (unwarranted) praise from a worthy competitor, but thank you.
I guess that either way around would do but it was logic that dictated my sentence…
Easy for one [Edited by Harry] – Hard for the many [… and again, sorry!] 😉8th January 2020 at 7:44 pm #45153ThompsonjMember
I’m tired and I’m ill. Can someone please explain (in non-cryptic language!) how 9A works?10th January 2020 at 12:12 pm #45178
It is too late to help you now for the points but for your knowledge…
First reverse the ciphertext then decrypt it as a Vigenere cipher with the keyphrase ‘onesmallsteponegiantleap’
- You must be logged in to reply to this topic.